Here you can find the source of distance(lat1, lon1, lat2, lon2)
exports.distance = function(lat1, lon1, lat2, lon2) { var radlat1 = Math.PI * lat1/180; var radlat2 = Math.PI * lat2/180; var radlon1 = Math.PI * lon1/180; var radlon2 = Math.PI * lon2/180; var theta = lon1-lon2; var radtheta = Math.PI * theta/180; var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta); dist = Math.acos(dist);//from www . ja v a 2 s . c o m dist = dist * 180/Math.PI; dist = dist * 60 * 1.1515; return dist * 1.609344; }
function calculateDistance(lat2, lon2) { var R = 3959; var lat1 = 47.3193057; var lon1 = -93.2895824; var dLat = (lat2 - lat1).toRad(); var dLon = (lon2 - lon1).toRad(); var a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.cos(lat1.toRad()) * Math.cos(lat2.toRad()) * Math.sin(dLon / 2) * Math.sin(dLon / 2); ...
function distance(lat1, lon1, lat2, lon2) { var R = 6371; var a = 0.5 - Math.cos((lat2 - lat1) * Math.PI / 180)/2 + Math.cos(lat1 * Math.PI / 180) * Math.cos(lat2 * Math.PI / 180) * (1 - Math.cos((lon2 - lon1) * Math.PI / 180))/2; var m = R * 2 * Math.asin(Math.sqrt(a))*1000; return Math.floor(m);
function distance(lat1,lon1,lat2,lon2) { var R = 6371; var dLat = deg2rad(lat2-lat1); var dLon = deg2rad(lon2-lon1); var a = Math.sin(dLat/2) * Math.sin(dLat/2) + Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) * Math.sin(dLon/2) * Math.sin(dLon/2) ; ...
function Point(x, y) { this.x = x; this.y = y; function randomPoint() { var randomx = randomNumber(WIDTH); var randomy = randomNumber(HEIGHT); var randomPoint = new Point(randomx, randomy); return randomPoint; ...
Math.distance = function(x1, x2, y1, y2){ var x = x2 - x1; var y = y2 - y1; return Math.sqrt(x * x + y * y); };