Java Utililty Methods Array Max Value

List of utility methods to do Array Max Value

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Description

The list of methods to do Array Max Value are organized into topic(s).

Method

doublemax(double[] series)
Finds the maximal value in timeseries. 
if (countNaN(series) == series.length) {
    return Double.NaN;
double max = Double.MIN_VALUE;
for (int i = 0; i < series.length; i++) {
    if (max < series[i]) {
        max = series[i];
return max;
doublemax(double[] vals)
max 
if (vals.length == 0) {
    return Double.NaN;
double[] range = range(vals);
return range[1];
doublemax(double[] values)
Calculates the maximum over an given array of doubles. 
try {
    double max = values[0];
    for (double v : values) {
        if (v > max)
            max = v;
    return max;
} catch (ArrayIndexOutOfBoundsException e) {
...
intmax(double[] values)
Find the maximum value in an array of double values. 
int maxIdx = -1;
for (int i = 0; i < values.length; i++) {
    if ((maxIdx == -1) || (values[i] > values[maxIdx])) {
        maxIdx = i;
return maxIdx;
doublemax(double[] values)
max 
Arrays.sort(values);
return maxOfSortedValues(values);
doublemax(double[] x)
Returns the highest element of `x`, NaN values are ignored. 
return max(x, true);
doublemax(final double aval, double[] b, final int bi, final int len)
max 
double ret = aval;
for (int i = bi; i < bi + len; i++)
    ret = Math.max(ret, b[i]);
return ret;
doublemax(final double... doubles)
Maximum of several double 
double max = doubles[0];
for (final double real : doubles) {
    max = real > max ? real : max;
return max;
doublemax(final double[] array)
max 
double d = Double.MIN_VALUE;
for (int i = 0; i < array.length; i++) {
    d = Math.max(array[i], d);
return d;
doubleMax(final double[] input)
Max 
if (input == null || input.length < 1) {
    return 0;
double output = input[0];
for (int i = 1; i < input.length; i++) {
    if (input[i] > output) {
        output = input[i];
return output;