Java Utililty Methods Array Max Value

List of utility methods to do Array Max Value

Description

The list of methods to do Array Max Value are organized into topic(s).

Method

intmax(int[] arr)
max
int max = Integer.MIN_VALUE;
for (int i : arr)
    max = Math.max(max, i);
return max;
intmax(int[] arr)
max
int maxIndex = 0;
int maxValue = arr[0];
for (int i = 1; i < arr.length; i++) {
    if (maxValue < arr[i]) {
        maxIndex = i;
        maxValue = arr[i];
return maxIndex;
intmax(int[] arr)
Returns the maximum element in the specified integer array.
if (arr == null)
    throw new IllegalArgumentException("The specified array may not be null");
if (arr.length == 0)
    throw new IllegalArgumentException("The specified array must have at least one element");
int n = arr[0];
for (int i = 1; i < arr.length; i++)
    if (arr[i] > n)
        n = arr[i];
...
intmax(int[] arr)
Find max value in an array of integers.
if (arr == null || arr.length == 0) {
    throw new IllegalArgumentException("Array cannot be null or empty");
int maxVal = Integer.MIN_VALUE;
for (int i : arr) {
    if (i > maxVal) {
        maxVal = i;
return maxVal;
intmax(int[] arr, int count)
max
int r = Integer.MIN_VALUE;
for (int i = 0; i < count; i++)
    r = Math.max(r, arr[i]);
return r;
intmax(int[] array)
Finds the maximum of an array of integers.
int maximum = Integer.MIN_VALUE;
for (int i = 0; i < array.length; i++) {
    if (maximum < array[i]) {
        maximum = array[i];
return maximum;
intmax(int[] array)
max
int maxValue = array[0];
for (int aVector : array) {
    if (maxValue < aVector) {
        maxValue = aVector;
return maxValue;
intmax(int[] array)
max
int max = -Integer.MAX_VALUE;
for (int a : array) {
    if (a > max) {
        max = a;
return max;
intmax(int[] array)
max
if (array.length == 0) {
    throw new RuntimeException("Array is empty.");
int max = array[0];
for (int i = 0; i < array.length; i++) {
    if (array[i] > max) {
        max = array[i];
return max;
intmax(int[] array)
max
int i, size = array.length;
int m = array[0];
for (i = 1; i < size; i++)
    m = Math.max(m, array[i]);
return m;