Java Utililty Methods Array Max Value

List of utility methods to do Array Max Value

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Description

The list of methods to do Array Max Value are organized into topic(s).

Method

byte[]max(byte[] lArray, byte[] rArray)
max 
int cmp = compare(lArray, 0, lArray.length, rArray, 0, rArray.length);
if (cmp >= 0) {
    return lArray;
} else {
    return rArray;
bytemax(byte[] values)
Get the maximum value in an array subset 
return max(values, 0, values.length);
Dmax(D... comparables)
Returns the maximum value. 
D max = null;
for (int i = 0; i < comparables.length; i++) {
    D element = comparables[i];
    if (element != null) {
        if (max == null || max.compareTo(element) < 0) {
            max = element;
return max;
doublemax(double array[], int start, int length)
max 
double max = array[start];
final int end = start + length;
for (int i = start + 1; i < end; i++) {
    double v = array[i];
    if (v > max) {
        max = v;
return max;
doublemax(double values[])
Finds maximum value in the given vector. 
double max = Double.NEGATIVE_INFINITY;
for (double value : values) {
    if (value > max)
        max = value;
return max;
doublemax(double values[], int size)
max 
if (values == null || size == 0) {
    return Double.NaN;
double r = Double.NEGATIVE_INFINITY;
for (int i = 0; i < size; i++) {
    double v = values[i];
    if (!Double.isNaN(v) && r < v) {
        r = v;
...
doublemax(double... a)
Computes the maximum value of a vararg of doubles. 
if (a == null) {
    return 0;
if (a.length == 0) {
    return 0;
double max = Double.MIN_VALUE;
for (double d : a) {
...
doublemax(double... arr)
max 
double max = Double.MIN_VALUE;
for (double d : arr)
    if (d > max)
        max = d;
return max;
doublemax(double... ds)
max 
if (ds.length < 2) {
    throw new IllegalArgumentException("Input values cannot be fewer than 2");
double max_value = ds[0];
for (int i = 1; i < ds.length; i++) {
    if (ds[i] > max_value) {
        max_value = ds[i];
return max_value;
doublemax(double... ds)
max 
double maxv = ds[0];
for (int i = 1; i < ds.length; i++) {
    maxv = Math.max(ds[i], maxv);
return maxv;