List of usage examples for java.lang Math sqrt
@HotSpotIntrinsicCandidate public static double sqrt(double a)
From source file:Main.java
public static float getNormalizeScaling(final float x, final float y, final float z) { return (float) (1.0 / Math.sqrt(x * x + y * y + z * z)); }
From source file:Main.java
public static float distance(float x1, float y1, float x2, float y2) { Log.d("Data: ", "" + Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2))); return (float) Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }
From source file:Main.java
public static double calcularHipotenusa(double catetoA, double catetoB) { //TODO suponemos valores correctos return Math.sqrt(Math.pow(catetoA, 2) + Math.pow(catetoB, 2)); }
From source file:Main.java
public static int calcularForca(float x, float y, float z) { int forca = (int) Math.sqrt((x * x + y * y + z * z)); return forca - GRAVIDADE; }
From source file:Main.java
public static float getDistance(float x1, float y1, float x2, float y2) { return (float) Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }
From source file:Main.java
private static float distance(Context context, float diff) { float distanceInPx = (float) Math.sqrt(diff * diff); return pxToDp(context, distanceInPx); }
From source file:Main.java
private static float calDistance(float x1, float y1, float x2, float y2) { return (float) Math.sqrt(Math.pow(x1 - x2, 2) + Math.pow(y1 - y2, 2)); }
From source file:Main.java
public static double calculateDPI(int width, int height, double screenSize) { return Math.sqrt(Math.pow(width, 2) + Math.pow(height, 2)) / screenSize; }
From source file:Main.java
public static float getSampleStdDev(float[] values) { return (float) Math.sqrt(getSampleVariance(values)); }
From source file:Main.java
public static float[] naivMatrixMultiply(float[] B, float[] A) { int mA, nA, mB, nB; mA = nA = (int) Math.sqrt(A.length); mB = nB = (int) Math.sqrt(B.length); if (nA != mB) throw new RuntimeException("Illegal matrix dimensions."); float[] C = new float[mA * nB]; for (int i = 0; i < mA; i++) for (int j = 0; j < nB; j++) for (int k = 0; k < nA; k++) C[i + nA * j] += (A[i + nA * k] * B[k + nB * j]); return C;//from ww w. j a v a 2 s. co m }