Remove path and file information from a filename returning only its extension component
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
/*
Derby - Class org.apache.derby.iapi.util.PropertyUtil
Licensed to the Apache Software Foundation (ASF) under one or more
contributor license agreements. See the NOTICE file distributed with
this work for additional information regarding copyright ownership.
The ASF licenses this file to you under the Apache License, Version 2.0
(the "License"); you may not use this file except in compliance with
the License. You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
*/
public class Main {
/**
* Remove path and file information from a filename returning only its
* extension component
*
* @param uri The filename
* @return The filename extension (with starting dot!) or null if filename extension is not found
*/
public static String getExtension(String uri) {
int dot = uri.lastIndexOf('.');
if (dot > -1) {
uri = uri.substring(dot);
int slash = uri.lastIndexOf('/');
if (slash > -1) {
return null;
} else {
int sharp = uri.lastIndexOf('#');
if (sharp > -1) {
// uri starts with dot already
return uri.substring(0, sharp);
} else {
int mark = uri.lastIndexOf('?');
if (mark > -1) {
// uri starts with dot already
return uri.substring(0, mark);
} else {
return uri;
}
}
}
} else {
return null;
}
}
}
Related examples in the same category
