Sort Numbers
/*
* Copyright (c) 2000 David Flanagan. All rights reserved.
* This code is from the book Java Examples in a Nutshell, 2nd Edition.
* It is provided AS-IS, WITHOUT ANY WARRANTY either expressed or implied.
* You may study, use, and modify it for any non-commercial purpose.
* You may distribute it non-commercially as long as you retain this notice.
* For a commercial use license, or to purchase the book (recommended),
* visit http://www.davidflanagan.com/javaexamples2.
*/
/**
* This class demonstrates how to sort numbers using a simple algorithm
*/
public class SortNumbers {
/**
* This is a very simple sorting algorithm that is not very efficient when
* sorting large numbers of things
*/
public static void sort(double[] nums) {
// Loop through each element of the array, sorting as we go.
// Each time through, find the smallest remaining element, and move it
// to the first unsorted position in the array.
for (int i = 0; i < nums.length; i++) {
int min = i; // holds the index of the smallest element
// find the smallest one between i and the end of the array
for (int j = i; j < nums.length; j++) {
if (nums[j] < nums[min])
min = j;
}
// Now swap the smallest one with element i.
// This leaves all elements between 0 and i sorted.
double tmp;
tmp = nums[i];
nums[i] = nums[min];
nums[min] = tmp;
}
}
/** This is a simple test program for the algorithm above */
public static void main(String[] args) {
double[] nums = new double[10]; // Create an array to hold numbers
for (int i = 0; i < nums.length; i++)
// Generate random numbers
nums[i] = Math.random() * 100;
sort(nums); // Sort them
for (int i = 0; i < nums.length; i++)
// Print them out
System.out.println(nums[i]);
}
}
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