Demonstrate unique() in list


#include <iostream>
#include <list>
using namespace std;

int main()
{
  list<int> listObject;
  list<int>::iterator p;

  for(int i = 0; i < 5; i++)
    for(int j = 0; j < 3; j++) 
       listObject.push_back(i);

  cout << "Orignal list: ";
  for(p = listObject.begin(); p != listObject.end(); p++)
    cout << *p << " ";
  cout << endl;

  listObject.unique(); // remove consecutive duplicates

  cout << "Modified list: ";
  for(p = listObject.begin(); p != listObject.end(); p++)
    cout << *p << " ";
  cout << endl;

  return 0;
}

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Demonstrate unique() in list : List « Data Structure « C++

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