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Open File Dialog « GUI Windows Form « C# / C Sharp
C# / C Sharp
GUI Windows Form
Open File Dialog
1.
Call ShowDialog() to display an OpenFileDialog
2.
Set InitialDirectory
3.
Set CheckFileExists to true
4.
Set Filter
5.
FileOk Action
6.
shows browsing for a set of files
7.
shows browsing for a file
8.
Open File Dialog with file types
9.
Demonstrates using an OpenFileDialog to prompt for a file name, and to open a file
10.
Show the use of some of the OpenFile dialog box
