Checks if the node can be appended on the given parent XML node - Java XML

Java examples for XML:XML Node

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Description

Checks if the node can be appended on the given parent XML node

Demo Code

/*//from ww  w.  ja  v a  2 s.  c om

   Licensed to the Apache Software Foundation (ASF) under one or more
   contributor license agreements.  See the NOTICE file distributed with
   this work for additional information regarding copyright ownership.
   The ASF licenses this file to You under the Apache License, Version 2.0
   (the "License"); you may not use this file except in compliance with
   the License.  You may obtain a copy of the License at

       http://www.apache.org/licenses/LICENSE-2.0

   Unless required by applicable law or agreed to in writing, software
   distributed under the License is distributed on an "AS IS" BASIS,
   WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
   See the License for the specific language governing permissions and
   limitations under the License.

 */
//package com.java2s;

import org.w3c.dom.Node;

public class Main {
    /**
     * Checks if the node can be appended on the given parent node
     *
     * @param node
     *            The given node
     * @param parentNode
     *            The given parent node
     * @return True if the given node can be appended on the parent node
     */
    public static boolean canAppend(Node node, Node parentNode) {
        if (node == null || parentNode == null || node == parentNode
                || isAncestorOf(node, parentNode)) {
            return false;
        }
        return true;
    }

    /**
     * Checks whether a node is ancestor of another node.
     *
     * @param node
     *            The potential ancestor node
     * @param descendant
     *            The potential descendant node
     * @return True if node is ancestor of the descendant node
     */
    public static boolean isAncestorOf(Node node, Node descendant) {
        if (node == null || descendant == null) {
            return false;
        }
        for (Node currentNode = descendant.getParentNode(); currentNode != null; currentNode = currentNode
                .getParentNode()) {
            if (currentNode == node) {
                return true;
            }
        }
        return false;
    }
}

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