Search String for last Index Of Any character in it - Java java.lang

Java examples for java.lang:String Index

  1. HOME
  2. Java
  3. java.lang
  4. String Index

Description

Search String for last Index Of Any character in it

Demo Code


public class Main{
    public static void main(String[] argv){
        String string = "java2s.com";
        char[] anyOf = new char[]{'b','o','o','k','2','s','.','c','o','m','','1',};
        System.out.println(lastIndexOfAny(string,anyOf));
    }//from w ww.  j a  v a  2 s .  co  m
    public static int lastIndexOfAny(String string, char[] anyOf) {
        int highestIndex = -1;
        for (char c : anyOf) {
            int index = string.lastIndexOf(c);
            if (index > highestIndex) {
                highestIndex = index;

                if (index == string.length() - 1)
                    break;
            }
        }

        return highestIndex;
    }
    public static int lastIndexOfAny(String string, char[] anyOf,
            int startIndex) {
        String substring = string.substring(0, startIndex + 1);
        int lastIndexInSubstring = lastIndexOfAny(substring, anyOf);
        if (lastIndexInSubstring < 0)
            return -1;
        else
            return lastIndexInSubstring;
    }
    public static int lastIndexOfAny(String string, char[] anyOf,
            int startIndex, int count) {
        int leftMost = startIndex + 1 - count;
        int rightMost = startIndex + 1;
        String substring = string.substring(leftMost, rightMost);
        int lastIndexInSubstring = lastIndexOfAny(substring, anyOf);
        if (lastIndexInSubstring < 0)
            return -1;
        else
            return lastIndexInSubstring + leftMost;
    }
}

Related Tutorials