Java Regex URL Validate isUrn(String value)

Here you can find the source of isUrn(String value)

Description

is Urn

License

Apache License

Declaration

public static boolean isUrn(String value) 

Method Source Code

//package com.java2s;
/*//from w  ww  .  j a  v  a2 s.c o m
 * Copyright 2012 Lev Khomich
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.util.regex.Pattern;

public class Main {
    private static final Pattern URN_PATTERN = Pattern
            .compile("urn:[a-zA-Z0-9][a-zA-Z0-9-]{1,31}:.+");

    public static boolean isUrn(String value) {
        return URN_PATTERN.matcher(value).matches();
    }
}

Related

  1. isURL(String url)
  2. isUrl(String x)
  3. isUrlAddress(String text)
  4. isUrlFile(String filePath)
  5. isUrlWithUserInfo(String str)