Here you can find the source of isUrl(String x)
public static boolean isUrl(String x)
//package com.java2s; /*//from w ww. ja v a2 s . c o m * Copyright 1998-2012 Linux.org.ru * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ import java.util.regex.Pattern; public class Main { private static final Pattern isUrl = Pattern.compile( "(((https?)|(ftp))://(([0-9\\p{L}.-]+\\.\\p{L}+)|(\\d+\\.\\d+\\.\\d+\\.\\d+))(:[0-9]+)?(/[^ ]*)?)|(mailto:[a-z0-9_+-.]+@[0-9a-z.-]+\\.[a-z]+)|(news:[a-z0-9.-]+)|(((www)|(ftp))\\.(([0-9a-z.-]+\\.[a-z]+(:[0-9]+)?(/[^ ]*)?)|([a-z]+(/[^ ]*)?)))", Pattern.CASE_INSENSITIVE); public static boolean isUrl(String x) { return isUrl.matcher(x).matches(); } }