Java Utililty Methods Regex Number Validate

List of utility methods to do Regex Number Validate

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Description

The list of methods to do Regex Number Validate are organized into topic(s).

Method

booleanisNumeric(String str)
is Numeric 
Matcher isNum = pattern.matcher(str);
if (!isNum.matches()) {
    return false;
return true;
booleanisNumeric(String text)
Validation method for Number Format (decimal is excluded) 
if (isEmpty(text)) {
    return false;
Pattern p = Pattern.compile("[0-9]*");
return p.matcher(text.trim()).matches();
booleanisNumeric(String value)
Indicates whether the given value is numeric. 
return NUMERIC_PATTERN.matcher(value).matches();
booleanisNumericAndCanNull(String src)
is Numeric And Can Null 
Pattern numericPattern = Pattern.compile("^[0-9]+$");
if ((src == null) || (src.equals("")))
    return true;
boolean return_value = false;
if ((src != null) && (src.length() > 0)) {
    Matcher m = numericPattern.matcher(src);
    if (m.find())
        return_value = true;
...
booleanisNumericAndCanNull(String src)
is Numeric And Can Null 
Pattern numericPattern = Pattern.compile("^[0-9]+$");
if (src == null || src.equals(""))
    return true;
boolean return_value = false;
if (src != null && src.length() > 0) {
    Matcher m = numericPattern.matcher(src);
    if (m.find()) {
        return_value = true;
...
booleanisNumString(String txt)
is Num String 
return isEqualsFormat("^\\d+(,\\d+)*$", txt);
longparseNumber(String in)
parse Number 
in = in.trim();
in = in.replaceAll(",", ".");
try {
    return Long.parseLong(in);
} catch (NumberFormatException e) {
final Matcher m = Pattern.compile("([\\d.,]+)\\s*(\\w)").matcher(in);
m.find();
...
intparseNumber(String input)
parse Number 
int num;
if (containsNumbers(input)) {
    input = stripNumber(input);
    num = Integer.parseInt(input);
} else
    throw new NumberFormatException("Not a readable number \"" + input + "\"");
return num;
intparseNumber(String input)
parse Number 
int num;
input = onlyNums.matcher(input).replaceAll("");
if (input.length() > 0)
    num = Integer.parseInt(input);
else
    throw new NumberFormatException("Not a readable number \"" + input + "\"");
return num;
longparseNumber(String s)
parse Number 
if (!isInitialized)
    init();
s = s.toLowerCase();
try {
    return Long.parseLong(s);
} catch (NumberFormatException e) {
    if (numberValues.containsKey(s)) {
        return numberValues.get(s);
...