List of utility methods to do Regex Number Validate
boolean | isNumberLiteral(String s) Check whether a string resembles a valid number literal. return isHexLiteral(s) || isBinaryLiteral(s) || isDecimalLiteral(s);
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boolean | isNumberOfShownValue(String inputString) is Number Of Shown Value String regex = "^[1-9]\\d*"; return getCheckValue(regex, inputString); |
boolean | isNumeric(String as_argument) check if given argument is numeric. boolean return_value = isOneMatched(sNUMERIC_PATTERNS, as_argument); return return_value; |
boolean | isNumeric(String input) is Numeric boolean result = false; if (input != null) { result = NUMERIC_PATTERN.matcher(input).matches(); return result; |
boolean | isNumeric(String number) is Numeric boolean isValid = false; String expression = "[0-9]*"; CharSequence inputStr = number; Pattern pattern = Pattern.compile(expression); Matcher matcher = pattern.matcher(inputStr); if (matcher.matches()) { isValid = true; return isValid; |
boolean | isNumeric(String s) Returns true if String s is numeric (i.e., the Digit POSIX character class) characters and nothing else. if (!hasLength(s)) { return false; Matcher m = DIGIT_REGEX.matcher(s); return m.matches(); |
boolean | isNumeric(String str) Tests whether a given string can be converted to an integer. return Pattern.matches("\\d+", str); |
boolean | isNumeric(String str) is Numeric Pattern pattern = Pattern.compile("\\d+\\.\\d+$|-\\d+\\.\\d+$"); Pattern pattern2 = Pattern.compile("[0-9]*"); return pattern.matcher(str).matches() || pattern2.matcher(str).matches(); |
boolean | isNumeric(String str) is Numeric Pattern pattern = Pattern.compile("[0-9]*"); return pattern.matcher(str).matches(); |
boolean | isNumeric(String str) is Numeric if (isNullOrEmpty(str)) { return false; String NUMERIC_PATTERN = "^(-?\\d+)(\\.\\d+)?$"; Pattern pattern = Pattern.compile(NUMERIC_PATTERN); Matcher matcher = pattern.matcher(str); return matcher.matches(); |