Here you can find the source of appendHex(A sb, byte[] array, int offset, int len, char sep)
public static <A extends Appendable> A appendHex(A sb, byte[] array, int offset, int len, char sep) throws IOException
//package com.java2s; /*/* w w w .j av a2s . c o m*/ * Licensed to the Apache Software Foundation (ASF) under one * or more contributor license agreements. See the NOTICE file * distributed with this work for additional information * regarding copyright ownership. The ASF licenses this file * to you under the Apache License, Version 2.0 (the * "License"); you may not use this file except in compliance * with the License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, * software distributed under the License is distributed on an * "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY * KIND, either express or implied. See the License for the * specific language governing permissions and limitations * under the License. */ import java.io.IOException; public class Main { public static final char EMPTY_HEX_SEPARATOR = '\0'; public static final String HEX_DIGITS = "0123456789abcdef"; public static <A extends Appendable> A appendHex(A sb, byte[] array, int offset, int len, char sep) throws IOException { if (len <= 0) { return sb; } for (int curOffset = offset, maxOffset = offset + len; curOffset < maxOffset; curOffset++) { byte b = array[curOffset]; if ((curOffset > offset) && (sep != EMPTY_HEX_SEPARATOR)) { sb.append(sep); } sb.append(HEX_DIGITS.charAt((b >> 4) & 0x0F)); sb.append(HEX_DIGITS.charAt(b & 0x0F)); } return sb; } }