Here you can find the source of acosh(double a)
public static double acosh(double a)
//package com.java2s; /*/*from w w w . ja va 2 s.c o m*/ * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements. See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ public class Main { /** * Calculates inverse hyperbolic cosine of a {@code double} value. * <p> * Special cases: * <ul> * <li>If the argument is NaN, then the result is NaN. * <li>If the argument is +1, then the result is a zero. * <li>If the argument is positive infinity, then the result is positive infinity. * <li>If the argument is less than 1, then the result is NaN. * </ul> */ public static double acosh(double a) { return Math.log(Math.sqrt(a * a - 1.0d) + a); } /** * Returns {@code x <= 0 ? 0 : Math.floor(Math.log(x) / Math.log(base))} * @param base must be {@code > 1} */ public static int log(long x, int base) { if (base <= 1) { throw new IllegalArgumentException("base must be > 1"); } int ret = 0; while (x >= base) { x /= base; ret++; } return ret; } /** * Calculates logarithm in a given base with doubles. */ public static double log(double base, double x) { return Math.log(x) / Math.log(base); } }