Java tutorial
/** * Copyright (c) 2015-2016 Peti Koch * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package ch.petikoch.examples.mvvm_rxjava.utils; import com.google.common.collect.Iterables; import com.google.common.collect.Lists; import rx.Observable; import rx.Scheduler; import rx.Subscriber; import java.util.List; import java.util.stream.Collectors; import static java.util.Arrays.asList; /** * A RxJava {@link rx.Observable.Operator} which takes care to preserve stacktraces across asynchronous * {@link rx.Scheduler}-boundaries. * <p> * This {@link rx.Observable.Operator} is typically placed AFTER {@link Observable#observeOn(Scheduler)} or {@link * Observable#subscribeOn(Scheduler)}. * <p> * See <a href="https://github.com/ReactiveX/RxJava/issues/3521#issuecomment-163571622">RxJava Issue 3521</a> for more * background about the topic. This {@link rx.Observable.Operator} can be used as kind of a workaround for this unresolved * RxJava issue (concerning RxJava versions <= 1.1.0 and probably also later versions). * <p> * Advantages: Analysing issues (stacktraces) gets much simpler for asynchronous use cases, since you have a "full" stacktrace<br> * Disadvantage: Performance. Creating the internal RuntimeException-object to capture the stacktrace is "not cheap". * But since we are operating at an asynchronous boundary, this doesn't add much additional overhead and can probably be neglected */ public class PreserveFullStackTraceOperator<T> implements Observable.Operator<T, T> { private final RuntimeException asyncOriginStackTraceProvider = new RuntimeException("async origin"); private final long originThreadId = Thread.currentThread().getId(); // should be "enough" unique. See http://stackoverflow.com/a/591664/1662412 public static <T> PreserveFullStackTraceOperator<T> preserveFullStackTrace() { return new PreserveFullStackTraceOperator<>(); } @Override public Subscriber<? super T> call(Subscriber<? super T> child) { Subscriber<T> parent = new Subscriber<T>() { @Override public void onCompleted() { child.onCompleted(); } @Override public void onError(Throwable throwable) { if (Thread.currentThread().getId() != originThreadId) { List<StackTraceElement> originalStackTraceElements = Lists .newArrayList(throwable.getStackTrace()); List<StackTraceElement> additionalAsyncOriginStackTraceElements = asList( asyncOriginStackTraceProvider.getStackTrace()).stream() .filter(stackTraceElement -> !PreserveFullStackTraceOperator.class.getName() .equals(stackTraceElement.getClassName())) .collect(Collectors.toList()); Iterable<StackTraceElement> modifiedStackTraceElements = Iterables .concat(originalStackTraceElements, additionalAsyncOriginStackTraceElements); throwable.setStackTrace(Iterables.toArray(modifiedStackTraceElements, StackTraceElement.class)); } child.onError(throwable); } @Override public void onNext(T t) { child.onNext(t); } }; child.add(parent); return parent; } }