Example usage for java.lang Long parseLong

Introduction

In this page you can find the example usage for java.lang Long parseLong.

Prototype

public static long parseLong(String s) throws NumberFormatException

Source Link

Document

Parses the string argument as a signed decimal long .

Usage

From source file:Main.java

public static void main(String[] args) {
    System.out.println(Long.parseLong("12345"));

}

From source file:Main.java

public static void main(String[] argv) throws Exception {
    long l = Long.parseLong("123");
    System.out.println(l);//  w  w w  . ja  v  a2  s. com
}

From source file:Main.java

public static void main(String[] args) {
    String str = new String("10");
    long l = Long.parseLong(str);
    System.out.println(l);//from www .j a  va2 s  .com
}

From source file:Main.java

public static void main(String[] args) {
    ToLongFunction<String> i = (x) -> Long.parseLong(x);

    System.out.println(i.applyAsLong("2"));
}

From source file:Main.java

public static void main(String[] args) {
    ToLongBiFunction<String, String> i = (x, y) -> Long.parseLong(x) + Long.parseLong(y);

    System.out.println(i.applyAsLong("2", "2"));
}

From source file:Main.java

public static void main(String[] args) throws Exception {
    String str = "0.5";
    long l = Long.valueOf(str).longValue();
    // or//  w  w w . ja  v  a2 s .com
    Long L = Long.parseLong(str);
}

From source file:Main.java

public static void main(String[] args) {
    List<String> stringList = Arrays.asList("1", "2", "3", "4", "5");

    stringList.stream().mapToLong(n -> Long.parseLong(n)).filter(n -> n % 2 == 0).forEach(System.out::println);
}

From source file:Main.java

public static void main(String[] args) {
    Stream<String> s = Stream.of("1", "2", "3");

    double o = s.collect(Collectors.averagingLong(n -> Long.parseLong(n)));

    System.out.println(o);//w ww  .j av  a2  s  .  c  o  m
}

From source file:Main.java

public static void main(String[] args) {
    List<String> stringList = Arrays.asList("1.2", "2.2", "3", "4", "5");

    stringList.stream().flatMapToLong(n -> LongStream.of(Long.parseLong(n))).forEach(System.out::println);
}

From source file:Primes.java

public static void main(String[] args) {
    long[] prime = new long[MAX];

    long stop = DEFAULT_STOP;
    if (args.length == 1) {
        stop = Long.parseLong(args[0]);
    }//from   w ww  . j av  a 2  s .c  om

    prime[1] = FP; // P1 (ignore prime[0])
    long n = FP + 1; // odd candidates
    int j = 1; // numberFound

    boolean isPrime = true; // for 3

    do {

        if (isPrime) {
            if (j == MAX - 1) {
                // Grow array dynamically if needed
                long[] np = new long[MAX * 2];
                System.arraycopy(prime, 0, np, 0, MAX);
                MAX *= 2;
                prime = np;
            }
            prime[++j] = n; // P2
            isPrime = false;
        }
        n += 2; // P4

        for (int k = 2; k <= j && k < MAX; k++) { // P5, P6, P8
            long q = n / prime[k];
            long r = n % prime[k];
            if (r == 0) {
                break;
            }
            if (q <= prime[k]) { // P7
                isPrime = true;
                break;
            }
        }

    } while (n < stop); // P3

    for (int i = 1; i <= j; i++)
        System.out.println(prime[i]);
}