Java I/O How to - Zip String to a file with ZipOutputStream

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Question

We would like to know how to zip String to a file with ZipOutputStream.

Answer

//from   w w  w  .  ja  va 2s .  com

import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class MainClass {

  public static void main(String[] args) throws IOException {
    String outputFile = "new.zip";
    // Default to maximum compression
    int level = 9;
    int start = 1;

    FileOutputStream fout = new FileOutputStream(outputFile);
    ZipOutputStream zout = new ZipOutputStream(fout);
    zout.setLevel(level);
    for (int i = start; i < args.length; i++) {
      ZipEntry ze = new ZipEntry(args[i]);
      FileInputStream fin = new FileInputStream(args[i]);
      try {
        System.out.println("Compressing " + args[i]);
        zout.putNextEntry(ze);
        for (int c = fin.read(); c != -1; c = fin.read()) {
          zout.write(c);
        }
      } finally {
        fin.close();
      }
    }
    zout.close();
  }
}

The code above generates the following result.

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