To overload an operator, you use a special function called an operator function.
An operator function has the following form, where op is the symbol for the operator being overloaded:
operator op (argument-list)
For example, operator+() overloads the + operator and operator*() overloads the * operator.
The op has to be a valid C++ operator.
The following table lists Operators That Can Be Overloaded.
+ - * / % ^ & | ~ ! = < > += -= *= /= %= ^= &= |= << >> >>= <<= == != <= >= && || ++ -- , ->* -> () [] new delete new [] delete []
The following code converts the Time class to using an overloaded addition operator.
#include <iostream>
class Time { /*from w w w . j a va2 s . co m*/
private:
int hours;
int minutes;
public:
Time();
Time(int h, int m = 0);
void AddMin(int m);
void AddHr(int h);
void Reset(int h = 0, int m = 0);
Time operator+(const Time & t) const;
void Show() const;
};
Time::Time()
{
hours = minutes = 0;
}
Time::Time(int h, int m )
{
hours = h;
minutes = m;
}
void Time::AddMin(int m)
{
minutes += m;
hours += minutes / 60;
minutes %= 60;
}
void Time::AddHr(int h)
{
hours += h;
}
void Time::Reset(int h, int m)
{
hours = h;
minutes = m;
}
Time Time::operator+(const Time & t) const
{
Time sum;
sum.minutes = minutes + t.minutes;
sum.hours = hours + t.hours + sum.minutes / 60;
sum.minutes %= 60;
return sum;
}
void Time::Show() const
{
std::cout << hours << " hours, " << minutes << " minutes";
}
int main()
{
using std::cout;
using std::endl;
Time planning;
Time coding(2, 40);
Time fixing(5, 55);
Time total;
cout << "planning time = ";
planning.Show();
cout << endl;
cout << "coding time = ";
coding.Show();
cout << endl;
cout << "fixing time = ";
fixing.Show();
cout << endl;
total = coding + fixing;
// operator notation
cout << "coding + fixing = ";
total.Show();
cout << endl;
Time morefixing(3, 28);
cout << "more fixing time = ";
morefixing.Show();
cout << endl;
total = morefixing.operator+(total);
// function notation
cout << "morefixing.operator+(total) = ";
total.Show();
cout << endl;
return 0;
}
The code above generates the following result.
The following code shows how to overload the subtraction and multiplication operators.
#include <iostream>
class Time { /*from ww w. j a v a2s .c o m*/
private:
int hours;
int minutes;
public:
Time();
Time(int h, int m = 0);
void AddMin(int m);
void AddHr(int h);
void Reset(int h = 0, int m = 0);
Time operator+(const Time & t) const;
Time operator-(const Time & t) const;
Time operator*(double n) const;
void Show() const;
};
Time::Time() {
hours = minutes = 0;
}
Time::Time(int h, int m )
{
hours = h;
minutes = m;
}
void Time::AddMin(int m)
{
minutes += m;
hours += minutes / 60;
minutes %= 60;
}
void Time::AddHr(int h)
{
hours += h;
}
void Time::Reset(int h, int m)
{
hours = h;
minutes = m;
}
Time Time::operator+(const Time & t) const
{
Time sum;
sum.minutes = minutes + t.minutes;
sum.hours = hours + t.hours + sum.minutes / 60;
sum.minutes %= 60;
return sum;
}
Time Time::operator-(const Time & t) const
{
Time diff;
int tot1, tot2;
tot1 = t.minutes + 60 * t.hours;
tot2 = minutes + 60 * hours;
diff.minutes = (tot2 - tot1) % 60;
diff.hours = (tot2 - tot1) / 60;
return diff;
}
Time Time::operator*(double mult) const
{
Time result;
long totalminutes = hours * mult * 60 + minutes * mult;
result.hours = totalminutes / 60;
result.minutes = totalminutes % 60;
return result;
}
void Time::Show() const
{
std::cout << hours << " hours, " << minutes << " minutes";
}
int main()
{
using std::cout;
using std::endl;
Time movie_time(4, 35);
Time dinner_time(2, 47);
Time total;
Time diff;
Time adjusted;
cout << "movie_time time = ";
movie_time.Show();
cout << endl;
cout << "dinner_time time = ";
dinner_time.Show();
cout << endl;
cout << "total work time = ";
total = movie_time + dinner_time; // use operator+()
total.Show();
cout << endl;
diff = movie_time - dinner_time; // use operator-()
cout << "movie_time time - dinner_time time = ";
diff.Show();
cout << endl;
adjusted = total * 1.5; // use operator+()
cout << "adjusted work time = ";
adjusted.Show();
cout << endl;
return 0;
}
The code above generates the following result.