Sort by last name than first name : Sort « XSLT stylesheet « XML Tutorial






  1. XML Tutorial
  2. XSLT stylesheet
  3. Sort
File: Data.xml
<?xml version="1.0"?>
<addressbook>
  <address>
    <name>
      <title>Mr.</title>
      <first-name>Jack</first-name>
      <last-name>Smith</last-name>
    </name>
    <street>1234 Main Street</street>
    <city>New York</city>
    <state>WI</state>
    <zip>48392</zip>
  </address>
</addressbook>


File: Transform.xslt

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="text"/>

  <xsl:template match="/">
    <xsl:for-each select="addressbook/address">
      <xsl:sort select="name/last-name"/>
      <xsl:sort select="name/first-name"/>
      <xsl:if test="name/title">
        <xsl:value-of select="name/title"/>
        <xsl:text> </xsl:text>
      </xsl:if>
      <xsl:value-of select="name/first-name"/>
      <xsl:text> </xsl:text>
      <xsl:value-of select="name/last-name"/>
      <xsl:text>&#xA;</xsl:text>
      <xsl:value-of select="street"/>
      <xsl:text>&#xA;</xsl:text>
      <xsl:value-of select="city"/>
      <xsl:text>, </xsl:text>
      <xsl:value-of select="state"/>
      <xsl:text>  </xsl:text>
      <xsl:value-of select="zip"/>
      <xsl:text>&#xA;</xsl:text>
      <xsl:text>&#xA;</xsl:text>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

Output:
Mr. Jack Smith
1234 Main Street
New York, WI  48392








5.18.Sort
5.18.1.The Element is used to specify sort order for node-sets
5.18.2.sort order="descending" select="."
5.18.3.sort elements
5.18.4.sort order="descending"
5.18.5.sort data-type="number" order="descending"
5.18.6.sort by name()
5.18.7.sort by attribute: sort select="@joined" data-type="number" order="descending"
5.18.8.Sort by different data types and order
5.18.9.Sort in a for-each loop
5.18.10.Sort by last name than first name
5.18.11.sort select="." data-type="number"
5.18.12.sort select="xs:integer(.)"
5.18.13.sort select="."