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1. Oracle PL/SQL Tutorial
2. Regular Expressions Functions
3. REGEXP_SUBSTR

SQL>
SQL> create table history
  2  ( empno      NUMBER(4)
  3  , beginyear  NUMBER(4)
  4  , begindate  DATE
  5  , enddate    DATE
  6  , deptno     NUMBER(2)
  7  , msal       NUMBER(6,2)
  8  , comments   VARCHAR2(60)
  9  ) ;

Table created.

SQL>
SQL>
SQL>
SQL> insert into history values (9,2000,date '2000-01-01',date '2002-01-02',40, 950,'history for 9');

1 row created.

SQL> insert into history values (8,2000,date '2000-01-02', NULL       ,20, 800,'');

1 row created.

SQL> insert into history values (7,1988,date '2000-01-06',date '2002-01-07',30,1000,'');

1 row created.

SQL> insert into history values (6,1989,date '2000-01-07',date '2002-01-12',30,1300,'');

1 row created.

SQL> insert into history values (5,1993,date '2000-01-12',date '2002-01-10',30,1500,'history for 5');

1 row created.

SQL> insert into history values (4,1995,date '2000-01-10',date '2002-01-11',30,1700,'');

1 row created.

SQL> insert into history values (3,1999,date '2000-01-11', NULL       ,30,1600,'');

1 row created.

SQL> insert into history values (2,1986,date '2000-01-10',date '2002-01-08',20,1000,'history for 2');

1 row created.

SQL> insert into history values (1,1987,date '2000-01-08',date '2002-01-01',30,1000,'history for 1');

1 row created.

SQL> insert into history values (7,1989,date '2000-01-01',date '2002-05-12',30,1150,'history for 7');

1 row created.

SQL>
SQL>
SQL>
SQL> select comments
  2  ,      regexp_substr(comments, '\([^\)]+\)') as substring
  3  from   history
  4  where  comments like '%(%';

no rows selected

SQL>
SQL>
SQL> drop table history;

Table dropped.