Take a probability value (between 0 and 1) and returns a percentile value (for a continuous distribution) : PERCENTILE_CONT « Analytical Functions « Oracle PL/SQL Tutorial






The general format for this function is:

PERCENTILE_CONT (expr) WITHIN GROUP (ORDER BY expr [DESC |ASC]) OVER (query_partition_clause)]

SQL>
SQL> -- create demo table
SQL> create table myTable(
  2    id           NUMBER(2),
  3    value        NUMBER(6,2)
  4  )
  5  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into myTable(ID,  value)values (1,9);

1 row created.

SQL> insert into myTable(ID,  value)values (2,2.11);

1 row created.

SQL> insert into myTable(ID,  value)values (3,3.44);

1 row created.

SQL> insert into myTable(ID,  value)values (4,-4.21);

1 row created.

SQL> insert into myTable(ID,  value)values (5,10);

1 row created.

SQL> insert into myTable(ID,  value)values (6,3);

1 row created.

SQL> insert into myTable(ID,  value)values (7,-5.88);

1 row created.

SQL> insert into myTable(ID,  value)values (8,123.45);

1 row created.

SQL> insert into myTable(ID,  value)values (9,98.23);

1 row created.

SQL> insert into myTable(ID,  value)values (10,938.23);

1 row created.

SQL> insert into myTable(ID,  value)values (11,984.23);

1 row created.

SQL> insert into myTable(ID,  value)values (12,198.23);

1 row created.

SQL> insert into myTable(ID,  value)values (13,928.87);

1 row created.

SQL> insert into myTable(ID,  value)values (14,25.37);

1 row created.

SQL> insert into myTable(ID,  value)values (15,918.3);

1 row created.

SQL> insert into myTable(ID,  value)values (16,9.23);

1 row created.

SQL> insert into myTable(ID,  value)values (17,8.23);

1 row created.

SQL>
SQL> select * from myTable
  2  /

        ID      VALUE
---------- ----------
         1          9
         2       2.11
         3       3.44
         4      -4.21
         5         10
         6          3
         7      -5.88
         8     123.45
         9      98.23
        10     938.23
        11     984.23

        ID      VALUE
---------- ----------
        12     198.23
        13     928.87
        14      25.37
        15      918.3
        16       9.23
        17       8.23

17 rows selected.

SQL>
SQL>
SQL>
SQL> SELECT PERCENTILE_CONT (0.2) WITHIN GROUP (ORDER BY id )
  2  from myTable;

PERCENTILE_CONT(0.2)WITHINGROUP(ORDERBYID)
------------------------------------------
                                       4.2

SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table myTable
  2  /

Table dropped.

SQL>
SQL>








16.21.PERCENTILE_CONT
16.21.1.Take a probability value (between 0 and 1) and returns a percentile value (for a continuous distribution)
16.21.2.PERCENTILE_CONT(x) examines the percent rank values in each group until it finds one that is greater than or equal to x
16.21.3.select percentile_cont(0.5) within group (order by salary desc )