Using the LN function : LN « Numerical Math Functions « Oracle PL/SQL Tutorial






SQL> -- create demo table
SQL> create table myTable(
  2    id           NUMBER(2),
  3    value        NUMBER(6,2)
  4  )
  5  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into myTable(ID,  value)values (1,9)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (2,2.11)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (3,3.44)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (5,10)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (6,3)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (8,123.45)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (9,98.23)
  2  /

1 row created.

SQL>
SQL> select * from myTable
  2  /

        ID      VALUE
---------- ----------
         1          9
         2       2.11
         3       3.44
         5         10
         6          3
         8     123.45
         9      98.23

7 rows selected.

SQL>
SQL>
SQL>
SQL> SELECT LN(value) FROM myTable
  2  /

 LN(VALUE)
----------
2.19722458
.746687947
1.23547147
2.30258509
1.09861229
4.81583622
4.58731167

7 rows selected.

SQL>
SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table myTable
  2  /

Table dropped.

SQL>








14.13.LN
14.13.1.Using the LN function
14.13.2.select ln(32)
14.13.3.SIN(30*3.14159265/180) TANH(0.5) EXP(4) LOG(2,32) LN(32)