Find all employees who are younger than employee whose id is 9999 : Single Row Subquery « Query Select « Oracle PL/SQL Tutorial

SQL> create table emp
  2  ( empno      NUMBER(4)    constraint E_PK primary key
  3  , ename      VARCHAR2(8)
  4  , init       VARCHAR2(5)
  5  , job        VARCHAR2(8)
  6  , mgr        NUMBER(4)
  7  , bdate      DATE
  8  , sal        NUMBER(6,2)
  9  , comm       NUMBER(6,2)
 10  , deptno     NUMBER(2)    default 10
 11  ) ;

Table created.

SQL> insert into emp values(1,'Tom','N', 'Coder', 13,date '1965-12-17',  800 , NULL,  20);

1 row created.

SQL> insert into emp values(2,'Jack','JAM', 'Tester',6,date '1961-02-20',  1600, 300,   30);

1 row created.

SQL> insert into emp values(3,'Wil','TF','Tester',6,date '1962-02-22',  1250, 500,   30);

1 row created.

SQL> insert into emp values(4,'Jane','JM','Designer', 9,date '1967-04-02',  2975, NULL,  20);

1 row created.

SQL> insert into emp values(5,'Mary','P','Tester',6,date '1956-09-28',  1250, 1400,  30);

1 row created.

SQL> insert into emp values(6,'Black','R','Designer', 9,date '1963-11-01',  2850, NULL,  30);

1 row created.

SQL> insert into emp values(7,'Chris','AB','Designer', 9,date '1965-06-09',  2450, NULL,  10);

1 row created.

SQL>
SQL> select ename, init, bdate
  2  from   emp
  3  where  bdate > (select bdate
  4                  from   emp
  5                  where  empno = 99999);

no rows selected

SQL>
SQL>
SQL>
SQL> drop table emp;

Table dropped.

2.36.Single Row Subquery
	2.36.1.	Writing Single Row Subqueries
	2.36.2.	Show products that are more expensive than average
	2.36.3.	Using Single Row Operators
	2.36.4.	Subqueries in a HAVING Clause
	2.36.5.	Subqueries in a FROM Clause (Inline Views)
	2.36.6.	A Couple of Errors when using subqueries in a FROM Clause (Inline Views)
	2.36.7.	Subqueries May Not Contain an ORDER BY Clause
	2.36.8.	A query that returns a result based on 'other rows'
	2.36.9.	Use greater than in sub query( list all employees who is younger than No 7)
	2.36.10.	Return null from subquery
	2.36.11.	Not Equal subquery
	2.36.12.	Not IN subquery
	2.36.13.	Older than another employee
	2.36.14.	Earn more than any managers
	2.36.15.	Earn more money than all managers
	2.36.16.	Earn more than average
	2.36.17.	List all employees who are younger than Jane
	2.36.18.	Subqueries in the WHERE Clause: equals
	2.36.19.	Subqueries in the WHERE Clause: less than
	2.36.20.	Find all employees who are younger than employee whose id is 9999