1. Create whole path automatically when writing to a new file stackoverflow.comI want to write a new file with the Java FileWriter. I use it like this: |
2. The system cannot find the path specified with FileWriter stackoverflow.comI have this code: |
3. can we specfity directory path with the property file while using ResourceBundle class in java stackoverflow.comI want to place my properties files in some folder, but i am not able to read them because we can specify only the bundle name in static getBundle method on ... |
4. Setting Path Directory on File Reader stackoverflow.comQuestion:
I'm workin with text files on Java. On Ubuntu 10. |
5. Write a text file using stream stackoverflow.com
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6. FileInputStream with path contains wildcard stackoverflow.comI am getting full path for some files from database and then zip those files inside that path. So problem here is the path contains wildcards even for the directory and ... |
7. InputStream from relative path stackoverflow.comI have a relative file path (for example "/res/example.xls") and I would like to get an InputStream Object of that file from that path. I checked the JavaDoc and did not ... |
8. How to input filePath on FileReader stackoverflow.comI have this code that Reads a file from the file path given. I have hardcoded F://dom.txt. I need the user to input that filepath instead. How should i do it? Thanks |
9. Relative path of file in FileInputStream coderanch.com |
10. how to get InputStream from a file with absolute path? coderanch.com |
11. new FileWriter("path of the file").write("text") coderanch.com |
12. what the default path of FileInputStream() coderanch.com |
13. How to create an un-existed path using stream coderanch.comHi folks, currently I can save file to an existed path. like this ------------------------------------------------ String file=D:\\test\\test.txt BufferedInputStream bistr = new BufferedInputStream(conn.getInputStream()); FileOutputStream fostr = new FileOutputStream(file); BufferedOutputStream bostr = new BufferedOutputStream( fostr ); while(-1 != (bytesRead = bistr.read(buff, 0, buff.length))) bostr.write(buff, 0, bytesRead); ---------------------------------------------------------------- currenlty the path D:\\test\\ existes. I tried an an un-existed path, like D:\\test1\\ there is an error ... |
14. Inpust stream path issue coderanch.comI try to get the contnets of a file in my class. I use the following code snippet. But I find that the input streams 'rules' and 'is' are null. I guess that the path of the xml file is not being recongnized. Please help... String path =(String)req.getRealPath("/WEB-INF/").replace('\\','/'); String outPath=path.concat("/validator-rules.xml"); InputStream rules = Thread.currentThread().getContextClassLoader().getResourceAsStream(outPath); final InputStream is = Thread.currentThread().getContextClassLoader().getResourceAsStream("/WEB-INF/validation.xml"); |
15. File vs InputStream when getting a reference to file under the class path coderanch.comThe File constructor creates a file relative to the local path - where you started the JVM. Therefore, the file could only exist if the Sample.txt was in the current folder. ClassLoader.getSystemResource(AsStream) loads a resource relative to the classpath. That can include folders not inside the current folder. This is apparently the case. |
16. How to specify the Relative path of a file in fileinputstream? coderanch.comHow to mention the relative path of the file in fileinputstream? The directory structure is as follows,Inside the **model** folder i have a java file called GetContents.java I need to refer the input.xls( a file inside the template folder ) in GetContents.java file. I tried new FileInputStream("..\\..\\..\\template\\DevContentsTemplate.xls") CVT - src -action -model -GetContents.java -bean -form -utils -WebContent -WEB-INF -classes -action -model ... |
17. using dynamic path in FileOutputStream("") coderanch.com |
18. getAbsolutePath() doesn't return full path? coderanch.comHi All I'm stuck with a problem to get the path to my program or code at runtime. My structure within the IDE workplace is workplace/ ---classes/ -------com/ -----------domain/ ---------------package/ and then the classes. ---resources/ -------images/ and then images -------DerbyDB/ and its files The program runs well when started from my IDE (JCreator) with String path = new String(new File("").getAbsolutePath()+File.separator+"resources"+File.separator); But ... |
19. FileInputStream with relative path in a JAR java-forums.orgpublic void play() { try { [COLOR="Red"][B]FileInputStream fis = new FileInputStream( MP3.class.getResource("rickroll.mp3").getPath());[/B][/COLOR] BufferedInputStream bis = new BufferedInputStream(fis); player = new Player(bis); } catch (Exception e) { System.out.println("Problem playing file " + filename); System.out.println(e); } // run in new thread to play in background new Thread() { public void run() { try { player.play(); } catch (Exception e) { System.out.println(e); } } ... |
20. about file path in filereader forums.oracle.comI try to link a fixed "h:/" and a file's name variable. but it report i/o error. I have checked the dicName work well. so I think the problem is the filePath variable. can anyone help me? thanks. try { String dicName=jtxtInput.getText();//get dictionary name from jtextfield String filePath="h:/"+dicName; FileReader fr = new FileReader(filePath); ........ }catch(NullPointerException e){ System.out.println("null"); }catch (IOException ex) { ... |
21. InputStream using file at relative path forums.oracle.com |
22. How to get full path from InputStream ? forums.oracle.comDepends If the class loader is a standard one or close to it that uses jars as the source then you can use the methods of from getResourceAsStream() to get the file. The jar file. You would need to delve into the jar to get the file. If instead the xml file is in fact a file on the file system ... |
23. volume name of File path / getAbsolutePath, this is driving me insane forums.oracle.comallright, now here comes the problem. i have another application which uses these 2 files (a dj software). it spits out the filenames of these two tracks in an xml file with these path names: 1) /Mac/Users/tecxx/Music/file1.ogg 2) /Data/DJMUSIC/file2.ogg Note that this application adds the Volume name to both paths, but NOT /Volumes/. what i need to do now is match ... |
24. how to get InputStream from a file with absolute path? forums.oracle.com |