DateDiff("yyyy", Now, "10/10/03") : DateDiff « Date Functions « VBA / Excel / Access / Word






  1. VBA / Excel / Access / Word
  2. Date Functions
  3. DateDiff

DateDiff("yyyy", Now, "10/10/03")

 
Sub dateDiff3()
    Debug.Print DateDiff("yyyy", Now, "10/10/03")
End Sub








Related examples in the same category

1.DateDiff(interval, date1, date2[, firstdayofweek[, firstweekofyear]]) returns the interval between two specified dates
2.DateDiff returns the interval of time between two dates:
3.Difference between two dates in days and months:
4.returns the number of weeks between June 3, 2006 and September 30, 2006:
5.DateDiff() function returns the difference between two dates. The unit for the difference is specified as a string ( "s" for second, "m" for month, "yyyy" for year, and so on).
6.DateDiff("m", Now, "10/10/03")
7.DateDiff("m", "3/15/2000", Now)
8.Use DateDiff function