DateDiff(interval, date1, date2[, firstdayofweek[, firstweekofyear]]) returns the interval between two specified dates
Constant Value Year Starts with Week
vbUseSystem 0 Use the system setting.
vbFirstJan1 1 The week in which January 1 falls (the default setting).
vbFirstFourDays 2 The first week with a minimum of four days in the year.
vbFirstFullWeek 3 The first full week (7 days) of the year.
Related examples in the same category
1. | DateDiff returns the interval of time between two dates: | | |
2. | Difference between two dates in days and months: | | |
3. | returns the number of weeks between June 3, 2006 and September 30, 2006: | | |
4. | DateDiff() function returns the difference between two dates. The unit for the difference is specified as a string ( "s" for second, "m" for month, "yyyy" for year, and so on). | | |
5. | DateDiff("m", Now, "10/10/03") | | |
6. | DateDiff("yyyy", Now, "10/10/03") | | |
7. | DateDiff("m", "3/15/2000", Now) | | |
8. | Use DateDiff function | | |