The RegEx.Replace method works like string.Replace, except that it uses a regular expression.
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
string find = @"\bis\b";
string replace = "are";
Console.WriteLine (Regex.Replace ("This is a test", find, replace));
}
}
The output:
This are a test
The replacement string can reference the original match with the $0 substitution construct.
The following example wraps numbers within a string in angle brackets:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
string text = "10, 20, 30 and 40";
Console.WriteLine (Regex.Replace (text, @"\d+", @"<$0>"));
}
}
The output:
<10>, <20>, <30> and <40>
| java2s.com | Contact Us | Privacy Policy |
| Copyright 2009 - 12 Demo Source and Support. All rights reserved. |
| All other trademarks are property of their respective owners. |