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Any

Input:	IEnumerable<TSource>
Optional lambda expression:	TSource => TResult

Any returns true if the given expression is true for at least one element.


using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;

class Program
{
    static void Main()
    {
        bool hasAThree = new int[] { 2, 3, 4 }.Any(n => n == 3);  // true;
        Console.WriteLine(hasAThree);
    }
}

The output:


True

Any can do everything that Contains can do, and more:


using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;

class Program
{
    static void Main()
    {
        bool hasABigNumber = new int[] { 2, 3, 4 }.Any(n => n > 10);  // false;
        Console.WriteLine(hasABigNumber);
    }
}

The output:


False

Calling Any without an expression returns true if the sequence has one or more elements.

Here's another way to write the preceding query:


using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;

class Program
{
    static void Main()
    {
        bool hasABigNumber = new int[] { 2, 3, 4 }.Where(n => n > 10).Any(); 
        
        Console.WriteLine(hasABigNumber);
    }
}

The output:


False

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