jQuery ajaxError() show url and status

Description

jQuery ajaxError() show url and status

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<!DOCTYPE html>
<html>
<head>
<script 
 src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js">
</script>//  w w  w.  j ava  2 s.c om
<script>
$(document).ready(function(){
  $(document).ajaxError(function(e, xhr, opt){
     document.getElementById("demo").innerHTML = 
         "Error requesting " + 
         opt.url + 
         ": " + 
         xhr.status + 
         " " + 
         xhr.statusText;
  });
  $("button").click(function(){
     $("div").load("wrongfile.txt");
  });
});
</script>
</head>
<body>

<p id="demo"></p>

<div><h2>Here</h2></div>

<button>Change Content</button>

</body>
</html>



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