Javascript Number times(f)

Number.prototype.times=function(f){for(var i=0;i<this;f(i++));}

Number.prototype.times = function (f) {
  for(let i = 0; i < this; i++) {
    f.call(this, i);/*from  www .  jav a2s  . c  o m*/
  }
}

// Do something "n.times" (Simplifying "for" loops)
// https://www.codewars.com/kata/do-something-n-dot-times-simplifying-for-loops

Number.prototype.times = function (f) {
    for (var i = 0; i < this; i++) {
        f.call(this, i);//from   ww w.ja v a 2s  . c om
    }
}

Number.prototype.times = function(f) {
  for (var i = 0; i < this; i++) {
    f();/*ww  w . ja  va2 s. c o  m*/
  }
  return this;
}

Number.prototype.times = function(f) {
  for (var i = 0, n = Number(this); i < n; ++i)
    f(i);/*from   ww w . j  a  v a2  s  . co  m*/
};

10..times(i => console.log(i + 1));

// In case you got lost, here's precisely what you have to do: define a method Number.prototype.times that accepts a function f as an argument and executes it as many times as the integer it is called on (e.g. (100).times would execute something 100 times). The iteration variable i should be supplied to the anonymous function being executed in order to support looping through array elements.

Number.prototype.times = function(f) {
  Array.from({ length: this.valueOf() }, (v, i) => f(i))
}

Number.prototype.times = function(f) {
 var i = 0;/*from   w  ww  . j  av  a 2 s . c o m*/
 for(i; i < this; i++) {
  (function(num, that) {
   f.apply(num, [that]);
  })(i, this);
 }
};

Number.prototype.times = function (f) {
  for(var i = 0; i < this.valueOf(); i++) {
    f(i);/*from   ww  w. ja v  a 2  s .  c  o  m*/
  }
}