Convert a string and replace every letter with its position in the alphabet.
If anything in the text isn't a letter, ignore it and don't return it.
a being 1, b being 2, etc.
As an example:
function alphabetPosition(str){ } alphabet_position("The sunset sets at twelve o' clock.") Should return "20 8 5 19 21 14 19 5 20 19 5 20 19 1 20 20 23 5 12 22 5 15 3 12 15 3 11"
const alphabetPosition = (text) =>
text
.toLowerCase()
.split(' ')
.join('')
.split('')
.filter((x) => 'abcdefghijklmnopqrstuvwxyz'.indexOf(x) !== -1)
.map((x) => 'abcdefghijklmnopqrstuvwxyz'.indexOf(x) + 1)
.join(' ');
console.log(
alphabetPosition("The sunset sets at twelve o' clock."), // => "20 8 5 19 21 14 19 5 20 19 5 20 19 1 20 20 23 5 12 22 5 15 3 12 15 3 11"
alphabetPosition("The narwhal bacons at midnight.") // => "20 8 5 14 1 18 23 8 1 12 2 1 3 15 14 19 1 20 13 9 4 14 9 7 8 20"
);