Write a function to find the 2nd largest element in a binary search tree
function Tree(value) { this.value = value;/* ww w.jav a 2 s . c o m*/ this.left = null; this.right = null; } Tree.prototype.addNode = function(value) { var node = new Tree(value); if (this.left === null) { this.left = node; } else if (this.right === null) { this.right = node; } else { console.log("No positions left to add node on this tree"); console.log("Try adding it to a child"); } } function secondLargestValue(tree, highest, secondHighest) { if (tree.value > highest) { secondHighest = highest; highest = tree.value } else if (tree.value > secondHighest) { secondHighest = tree.value; } //Go right if we have the option and do not go left, cutting the dataset to traverse in half if (tree.right !== null) { secondHighest = secondLargestValue(tree.right, highest, secondHighest); } else if (tree.left !== null) { secondHighest = secondLargestValue(tree.left, highest, secondHighest); } return secondHighest; } var tree = new Tree(10); tree.addNode(15); tree.addNode(20); tree.left.addNode(23); tree.left.addNode(25); tree.right.addNode(27); tree.right.addNode(28); tree.right.right.addNode(2); tree.right.right.addNode(4); tree.right.right.right.addNode(220); console.log(secondLargestValue(tree, 0, 0)); //28