Javascript Array compareLexicographically(arr)

//### Problem 2. Lexicographically comparison
//* Write a script that compares two char arrays lexicographically (letter by letter).

Array.prototype.compareLexicographically = function (arr){
    for(var ind = 0; ind < Math.min(this.length, arr.length); ind++){
        if(arr[ind] !== this[ind]){
            return this[ind] < arr[ind] ? -1 : 1;
        }//  w w  w  .  j a v a 2  s .  c o  m
    }

    if(this.length != arr.length){
        this.length < arr.length ? -1 : 1;
    }

    return 0;
}

var a = 'abc'.split(''), b = 'acb'.split('');

console.log(a.compareLexicographically(b));

Array.prototype.compareLexicographically = function (arr) {
    for (var ind = 0; ind < Math.min(this.length, arr.length) ; ind++) {
        if (arr[ind] !== this[ind]) {
            return this[ind] < arr[ind] ? -1 : 1;
        }/*w w  w.j a v  a2  s .  c  om*/
    }

    if (this.length != arr.length) {
        this.length < arr.length ? -1 : 1;
    }

    return 0;
}

document.writeln(['a', 'b', 'c'].compareLexicographically(['a', 'b', 'c']));
document.writeln(['a', 'b', 'c'].compareLexicographically(['a', 'c', 'b']));
document.writeln(['a', 'c', 'b'].compareLexicographically(['a', 'b', 'c']));

// Write a script that compares two char arrays
// lexicographically (letter by letter).

Array.prototype.compareLexicographically = function (arr){
    for (var ind = 0; ind < Math.min(this.length, arr.length); ind++) {
        if (arr[ind] !== this[ind]) {
            return this[ind] < arr[ind] ? -1 : 1;
        }//from  w  w  w.j  a  v a  2 s  .c om
    }

    if (this.length != arr.length) {
        this.length < arr.length ? -1 : 1;
    }

    return 0;
}

console.log(['a', 'b', 'c'].compareLexicographically(['a', 'b', 'c']));
console.log(['a', 'b', 'c'].compareLexicographically(['a', 'c', 'b']));
console.log(['a', 'c', 'b'].compareLexicographically(['a', 'b', 'c']));