Java Path get path from zip file

import java.io.IOException;
import java.net.URI;
import java.nio.file.DirectoryStream;
import java.nio.file.FileSystem;
import java.nio.file.FileSystems;
import java.nio.file.Files;
import java.nio.file.Path;
import java.util.HashMap;
import java.util.Map;

public class Main {

   public static void main(String[] args) {
      Map<String, String> attributes = new HashMap<>();
      attributes.put("create", "true");
      try {/*from   www.j  a  v  a2  s  .c  o m*/
         URI zipFile = URI.create("jar:file:/home.zip");
         try (FileSystem zipFileSys = FileSystems.newFileSystem(zipFile, attributes);) {
            Path path = zipFileSys.getPath("docs");
            Files.createDirectory(path);
            try (DirectoryStream<Path> directoryStream = Files.newDirectoryStream(zipFileSys.getPath("/"));) {
               for (Path file : directoryStream) {
                  System.out.println(file.getFileName());
               }
            }
         }
      } catch (IOException e) {
         e.printStackTrace();
      }

   }
}