The third example uses a subquery to determine the value of deptno and mgr.
Instead of having two different subqueries for deptno and mgr, you can use a scalar subquery that returns multiple columns.
The number, data types, and order of the subquery columns must match the columns that are being updated.
SQL> SQL>-- from ww w . j a v a2 s. c o m SQL> drop table emp; Table dropped. SQL> create table emp( 2 empno NUMBER(4) primary key, 3 ename VARCHAR2(8) not null , 4 init VARCHAR2(5) not null , 5 job VARCHAR2(8) , 6 mgr NUMBER(4) , 7 bdate DATE not null , 8 msal NUMBER(6,2) not null , 9 comm NUMBER(6,2) , 10 deptno NUMBER(2) default 10) ; SQL> SQL> insert into emp values(7001,'SMITH','N', 'TRAINER', 7902,date '1975-12-17', 1800 , NULL, 20); SQL> insert into emp values(7002,'ALLEN','JAM','SALESREP',7006,date '1971-05-20', 1600, 300, 30); SQL> insert into emp values(7003,'WARD', 'TF' ,'SALESREP',7006,date '1972-03-02', 1250, 500, 10); SQL> insert into emp values(7004,'JACK', 'JM', 'MANAGER', 7009,date '1977-04-02', 2975, NULL, 20); SQL> insert into emp values(7005,'BROWN','P', 'SALESREP',7006,date '1976-09-28', 1250, 1400, 30); SQL> insert into emp values(7006,'BLAKE','R', 'MANAGER', 7009,date '1973-11-01', 2850, NULL, 10); SQL> insert into emp values(7007,'CLARK','AB', 'MANAGER', 7009,date '1975-06-09', 2450, NULL, 10); SQL> insert into emp values(7008,'SCOTT','DEF','TRAINER', 7004,date '1979-11-26', 3000, NULL, 20); SQL> insert into emp values(7009,'KING', 'CC', 'DIRECTOR',NULL,date '1972-10-17', 5000, NULL, 10); SQL> insert into emp values(7010,'BREAD','JJ', 'SALESREP',7006,date '1978-09-28', 1500, 0, 30); SQL> insert into emp values(7011,'ADAMS','AA', 'TRAINER', 7008,date '1976-12-30', 1100, NULL, 20); SQL> insert into emp values(7012,'JONES','R', 'ADMIN', 7006,date '1979-10-03', 8000, NULL, 30); SQL> insert into emp values(7902,'FORD', 'MG', 'TRAINER', 7004,date '1979-02-13', 3000, NULL, 20); SQL> insert into emp values(7934,'MARY', 'ABC','ADMIN', 7007,date '1972-01-23', 1300, NULL, 10); SQL> SQL> UPDATE emp 2 SET (deptno,mgr) = (SELECT deptno,mgr 3 FROM departments 4 WHERE location = 'BOSTON') 5 WHERE empno = 7012; 1 row updated. SQL> SQL> select * 2 from emp; EMPNO | ENAME | INIT | JOB | MGR | BDATE | MSAL --------- | -------- | ----- | -------- | --------- | ---------- | --------- COMM | DEPTNO --------- | --------- 07001.00 | SMITH | N | TRAINER | 07902.00 | 17-12-1975 | 01800.00 [N/A] | 00020.00 07002.00 | ALLEN | JAM | SALESREP | 07006.00 | 20-05-1971 | 01600.00 00300.00 | 00030.00 07003.00 | WARD | TF | SALESREP | 07006.00 | 02-03-1972 | 01250.00 00500.00 | 00010.00 EMPNO | ENAME | INIT | JOB | MGR | BDATE | MSAL --------- | -------- | ----- | -------- | --------- | ---------- | --------- COMM | DEPTNO --------- | --------- 07004.00 | JACK | JM | MANAGER | 07009.00 | 02-04-1977 | 02975.00 [N/A] | 00020.00 07005.00 | BROWN | P | SALESREP | 07006.00 | 28-09-1976 | 01250.00 01400.00 | 00030.00 07006.00 | BLAKE | R | MANAGER | 07009.00 | 01-11-1973 | 02850.00 [N/A] | 00010.00 EMPNO | ENAME | INIT | JOB | MGR | BDATE | MSAL --------- | -------- | ----- | -------- | --------- | ---------- | --------- COMM | DEPTNO --------- | --------- 07007.00 | CLARK | AB | MANAGER | 07009.00 | 09-06-1975 | 02450.00 [N/A] | 00010.00 07008.00 | SCOTT | DEF | TRAINER | 07004.00 | 26-11-1979 | 03000.00 [N/A] | 00020.00 07009.00 | KING | CC | DIRECTOR | [N/A] | 17-10-1972 | 05000.00 [N/A] | 00010.00 EMPNO | ENAME | INIT | JOB | MGR | BDATE | MSAL --------- | -------- | ----- | -------- | --------- | ---------- | --------- COMM | DEPTNO --------- | --------- 07010.00 | BREAD | JJ | SALESREP | 07006.00 | 28-09-1978 | 01500.00 00000.00 | 00030.00 07011.00 | ADAMS | AA | TRAINER | 07008.00 | 30-12-1976 | 01100.00 [N/A] | 00020.00 07012.00 | JONES | R | ADMIN | 07009.00 | 03-10-1979 | 08000.00 [N/A] | 00040.00 EMPNO | ENAME | INIT | JOB | MGR | BDATE | MSAL --------- | -------- | ----- | -------- | --------- | ---------- | --------- COMM | DEPTNO --------- | --------- 07902.00 | FORD | MG | TRAINER | 07004.00 | 13-02-1979 | 03000.00 [N/A] | 00020.00 07934.00 | MARY | ABC | ADMIN | 07007.00 | 23-01-1972 | 01300.00 [N/A] | 00010.00 14 rows selected. SQL>