Oracle SQL - NTILE descending order

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Introduction

The following query and result reverses the grouping: 

SELECT empno, ename, curr_salary, 
  NTILE(4) OVER(ORDER BY curr_salary desc, empno desc) nt 
FROM emp;

Demo

SQL>
SQL> drop table emp;

Table dropped.--  w  ww . j  a  v a  2 s. c  o  m

SQL> create table emp(
  2  empno        Number(3)  NOT NULL,
  3  ename        VARCHAR2(10 BYTE),
  4  hireDate     DATE,
  5  orig_salary  Number(8,2),
  6  curr_salary  Number(8,2),
  7  region       VARCHAR2(1 BYTE)
  8  );
SQL>
SQL> insert into emp values(1,'Alison',DATE '1996-03-21', 45000, NULL,  'E');
SQL> insert into emp values(2,'James',DATE  '1978-12-12', 23000, 32000, 'W');
SQL> insert into emp values(3,'Celia',DATE  '1982-10-24', NULL,  58000, 'E');
SQL> insert into emp values(4,'Robert',DATE '1984-01-15', 31000, NULL,  'W');
SQL> insert into emp values(5,'Linda',DATE  '1987-07-30', NULL,  53000, 'E');
SQL> insert into emp values(6,'David',DATE  '1990-12-31', 78000, NULL,  'W');
SQL> insert into emp values(7,'Jode',DATE  '1996-09-17', 21000, 29000, 'E');
SQL>
SQL> SELECT empno, ename, curr_salary,
  2    NTILE(4) OVER(ORDER BY curr_salary desc, empno desc) nt
  3  FROM emp;

     EMPNO ENAME      CURR_SALARY         NT
---------- ---------- ----------- ----------
         6 David                           1
         4 Robert                          1
         1 Alison                          2
         3 Celia            58000          2
         5 Linda            53000          3
         2 James            32000          3
         7 Jode             29000          4

7 rows selected.

SQL>

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