Nodejs String Contains contains( s, index)

Method Source Code

/*/*from  w  ww .  j  ava  2 s .  c  om*/

   Description:
      Check if a String has a give String
   
   Syntax:
      String.contains( s, index)
      
      Parameters:
         String s 
   
   Return:
      Boolean
      
   Sample:
      "I am the best and girls love me!".contains("best") == true
   
*/

String.prototype.contains   = function( s, index) {
   return this.indexOf(s,index||0) > -1;
}

Related

1. Contains( str )

   String.prototype.Contains = function( str )
       return this.indexOf( str ) > -1;
   };
   

2. Contains( textToCheck )

   String.prototype.Contains = function( textToCheck )
     return ( this.indexOf( textToCheck ) > -1 ) ;
   

3. containIgnoreCase(otherStr)

   String.prototype.containIgnoreCase = function (otherStr) {
       return this.toLowerCase().indexOf(otherStr.toLowerCase());
   

4. contains()

   String.prototype.contains = function() {
     var args = arguments;
     for (var i in args) {
       var str = args[i];
       if (typeof str === "string" && this.indexOf(str) > -1) {
         return true;
     return false;
   ...
   

5. contains()

   var fs = require('fs');
   var path = process.argv[2];
   var suffix = '.'+process.argv[3];
   var list =[];
   String.prototype.contains = function() {
       return String.prototype.indexOf.apply( this, arguments ) !== -1;
   };
   fs.readdir(path, function(err, files){
     if(!err){
   ...
   

6. contains()

   String.prototype.contains = function () {
     return String.prototype.indexOf.apply(this, arguments) !== -1;
   };
   

7. contains(a)

   String.prototype.contains = function (a) {
     if (this.indexOf(a) > -1)
       return true;
     else
       return false;
   };