Nodejs Number Check isPalindrome()

Method Source Code

Number.prototype.isPalindrome = function() {
  return this == this.reverse();
}

var max = 0/*w w w  .java  2  s .  com*/
  , x;

for (var i = 100; i < 999; i++) {
  for (var j = i; j < 999; j++) {
    x = i * j;
    if (x.isPalindrome() && x > max) {
      max = x;
    }
  }
}

console.log(max);

Related

1. isInRangeisInRange(lower, upper)

   (function(){
   "use strict";
   Number.prototype.isInRange = function isInRange(lower, upper){
     if (this >= lower && this <= upper){
       return true;
     if (this <= lower && this >= upper){
       return true;
     return false;
   };
   

2. isMultipleof(num)

   Number.prototype.isMultipleof = function (num) {
     if (this % num === 0) {
       return true;
     return false;
   var result = 0;
   for (var i = 1; i < 1000; i++) {
     if (i.isMultipleof(3) || i.isMultipleof(5) ) {
   ...
   

3. isNegativeZero()

   Number.prototype.isNegativeZero = function() {
     var n = this;
     return n === 0 && (((n = +n) || (1 / n)) < 0);
   

4. isPerfPow(nroot)

   Number.prototype.isPerfPow = function(nroot){
     var primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53];
     var root,log2,t;
     t = Math.abs(this);
     log2 = Math.floor(Math.log(t)/Math.LN2);
     if(this.isPow2()) return true;
     root = Math.round(Math.sqrt(t));
     if(t - (root * root) == 0){
       if(arguments.length  > 0){
   ...
   

5. isPositive()

   Number.prototype.isPositive = function() {
     return this > 0;
   

6. isPositive()

   Number.prototype.isPositive = function(){
     return this > 0;
   var numb = new Number(10);
   console.log(numb.isPositive());