Nodejs Number Calculate parseNumber(x)

Here you can find the source of parseNumber(x)

Method Source Code

function parseNumber(x){
  if(!isNaN(x)) return x;
  return parseFloat(x.substring(1, x.length - 1));
}

Related

  1. next()
    Number.prototype.next = function(){
        return this+1;
    };
    
  2. normalize(num)
    Number.prototype.normalize = function(num) {
      return this*180/num;
    };
    
  3. ordenar()
    #!/usr/bin/env node
    Number.prototype.ordenar = function () {
      return this.toString().split('').sort(up).join('');
    };
    function up (a,b) {
      return a > b ? 1 : a < b ? -1 : 0;
    var x = 0;
    var done= false;
    ...
    
  4. ordinal()
    Number.prototype.ordinal = function () {
        return this + (
            (this % 10 == 1 && this % 100 != 11) ? 'st' :
            (this % 10 == 2 && this % 100 != 12) ? 'nd' :
            (this % 10 == 3 && this % 100 != 13) ? 'rd' : 'th'
            );
    var ResetInput = function(){
        jQuery('input, textarea').each(function() {
    ...
    
  5. ordinalize()
    Number.prototype.ordinalize = function() {
        var abs = Math.abs(this);
        if (abs % 100 >= 11 && abs % 100 <= 13) {
            return this + 'th';
        abs = abs % 10;
        if (abs === 1) { return this + 'st'; }
        if (abs === 2) { return this + 'nd'; }
        if (abs === 3) { return this + 'rd'; }
    ...
    
  6. percentage(val)
    Number.prototype.percentage = function(val){
      return this * (val/100);
    };
    
  7. plural(a, b, c)
    Number.prototype.plural = function (a, b, c)
      if (this % 1)
        return b
      var v = Math.abs(this) % 100
      if (11 <= v && v <= 19)
        return c
      v = v % 10
      if (2 <= v && v <= 4)
    ...
    
  8. pluralA(ary)
    Number.prototype.pluralA = function (ary)
      return this.plural(ary[0], ary[1], ary[2])
    
  9. popCount()
    Number.prototype.popCount = function() {
      var v = this.valueOf();
      v = v - ((v >> 1) & 0x55555555);                
      v = (v & 0x33333333) + ((v >> 2) & 0x33333333); 
      return ((v + (v >> 4) & 0xF0F0F0F) * 0x1010101) >> 24;
    };