Nodejs Array Sum sum()

Method Source Code

Array.prototype.sum = function () {
    var length = this.length;
    var total = 0;
    for (var i = 0; i < length; i++) {
       total += this[i];//ww w  .  j a  v  a 2 s. c o  m
    }
    return total;
};

Related

1. sum()

   Array.prototype.sum = function() {
       var res = 0;
       for(var p in this)
     res += this[p];
       return res;
   };
   var s = [1, 2, 3].sum();
   

2. sum()

   Array.prototype.sum = function() {
     return this.reduce(function(prev, curr) {
       return prev + curr;
     });
   };
   module.exports = Array.prototype.sum;
   

3. sum()

   Array.prototype.sum  = function() {
       var res = 0;
       for(var p in this)
     res += this[p];
       return res;
   };
   var a = [1, 2, 3];
   console.log(0 in a);
   

4. sum()

   Array.prototype.sum = function() {
       var res = 0;
       for(var i=0;i<this.length;++i)
     res += this[i];
       return res;
   };
   var s = [1, 2, 3].sum();
   

5. sum()

   Array.prototype.sum = function () {
     var sum = 0;
     for (var i = 0; i < this.length; i++) {
       sum += this[i];
     };
     return sum;
   console.log([1, 3, 12, 33, 2].sum());
   

6. sum()

   const assert = require('assert')
   Array.prototype.sum = function() {
     return this.reduce((sum, el) => sum + el, 0)
   assert.equal([].sum(), 0)
   assert.equal([2, 5, 7].sum(), 14)
   

7. sum()

   Array.prototype.sum = function() {
       var res = 0;
       for(var p in this)
     res += this[p];
       return res;
   };
   var a = [1, 2, 3];
   var all_in = true;
   for(var i=0;i<5;++i)
   ...
   

8. sum()

   var ary1 = new Array(12, 55, 43, 32, 44);
   var ary2 = new Array(12, 33, 1);
   Array.prototype.sum = function() {
       var output = 0;
       for (var i = 0; i < this.length; i++) {
           output += this[i];
       return output;
   };
   ...
   

9. sum()

   Array.prototype.sum = function(){
     for(var i=0,sum=0;i<this.length;sum+=this[i++]);
     return sum;