Here you can find the source of mult2()
Array.prototype.mult2 = function() { for (var i = 0; i < this.length; i++) { this[i] = this[i] * 2;//from w ww. java 2s . co m } };
Array.prototype.mul = function(value) { var newArray = new Array(); for(var i=0; i<this.length; i++) { newArray[i] = this[i] * value; return newArray;
Array.prototype.mult = function(other) { if(isFinite(other)) other = new Array(this.length).fill(other); else console.assert(this.length == other.length, 'mult: len(a) != len(b)'); var ret = new Array(this.length); for(var i = 0; i < ret.length; i++) ret[i] = this[i] * other[i]; return ret; ...
Array.prototype.multipleConcat = function() { var initialArray = arguments[0]; if (arguments.length > 0) { for (var i = 1, arrayCount = arguments.length; i < arrayCount; i++ ) { initialArray.push.apply(initialArray, arguments[i]); return initialArray; }; ...
Array.prototype.multiples = function(multiple) { var multiples = []; for (var i = 0; i < this.length; i++){ multiples.push(this[i] * multiple); return multiples; console.log([1,2,3,4,5].multiples(5)); Array.prototype.myEach = function(someFunction){ ...
Array.prototype.multiply = function(a2) { var l1 = this.length; var l2 = a2.length; var len = (l1 < l2 ? l1 : l2); var result = new Array(len); for (var i = 0; i < len; i++) { result[i] = this[i] * a2[i]; return result; ...
Array.prototype.multiply = function(n){ results = [] for (var i = 0; i < this.length; i++){ for (var j = 0; j < n; j++){ results.push(this[i]) return results