Tests whether the given string is a valid XML 1.1 name. - Java XML

Java examples for XML:XML Schema

  1. HOME
  2. Java
  3. XML
  4. XML Schema

Description

Tests whether the given string is a valid XML 1.1 name.

Demo Code

/*// w w  w . j  a  v a 2s.c o  m

   Licensed to the Apache Software Foundation (ASF) under one or more
   contributor license agreements.  See the NOTICE file distributed with
   this work for additional information regarding copyright ownership.
   The ASF licenses this file to You under the Apache License, Version 2.0
   (the "License"); you may not use this file except in compliance with
   the License.  You may obtain a copy of the License at

       http://www.apache.org/licenses/LICENSE-2.0

   Unless required by applicable law or agreed to in writing, software
   distributed under the License is distributed on an "AS IS" BASIS,
   WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
   See the License for the specific language governing permissions and
   limitations under the License.

 */
import java.io.IOException;
import java.io.StringReader;
import java.io.StringWriter;
import java.io.Writer;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.Map;
import java.util.Set;
import org.w3c.dom.Attr;
import org.w3c.dom.DOMException;
import org.w3c.dom.DOMImplementation;
import org.w3c.dom.Document;
import org.w3c.dom.DocumentType;
import org.w3c.dom.Element;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main{
    /**
     * Tests whether the given string is a valid XML 1.1 name.
     */
    public static boolean isValidName11(String s) {
        int len = s.length();
        if (len == 0) {
            return false;
        }
        char c = s.charAt(0);
        int d = c / 32;
        int m = c % 32;
        if ((NAME11_FIRST_CHARACTER[d] & (1 << m)) == 0) {
            return false;
        }
        for (int i = 1; i < len; i++) {
            c = s.charAt(i);
            d = c / 32;
            m = c % 32;
            if ((NAME11_CHARACTER[d] & (1 << m)) == 0) {
                return false;
            }
        }
        return true;
    }
}

Related Tutorials