Java examples for XML:XML Node Child
Iterate over the children of a given XML node and return the first node that has a specific name.
/*/*from www . j a v a 2s. co m*/ * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements. See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. * */ //package com.java2s; import org.w3c.dom.Element; import org.w3c.dom.Node; import org.w3c.dom.NodeList; public class Main { /** * Iterate over the children of a given node and return the first node * that has a specific name. * @param parent the node to search child from. Can be <tt>null</tt>. * @param tagname the child name we are looking for. Cannot be <tt>null</tt>. * @return the first child that matches the given name or <tt>null</tt> if * the parent is <tt>null</tt> or if a child does not match the * given name. */ public static Element getChildByTagName(Node parent, String tagname) { if (parent == null) { return null; } NodeList childList = parent.getChildNodes(); final int len = childList.getLength(); for (int i = 0; i < len; i++) { Node child = childList.item(i); if (child != null && child.getNodeType() == Node.ELEMENT_NODE && child.getNodeName().equals(tagname)) { return (Element) child; } } return null; } }