Gets the XML line that declares the stylesheet. - Java XML

Java examples for XML:XML Declaration

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Description

Gets the XML line that declares the stylesheet.

Demo Code

/*/*ww w .  j  a  v  a  2s  .c  o  m*/
 * Balie - BAseLine Information Extraction
 * Copyright (C) 2004-2007  David Nadeau
 * 
 * This program is free software; you can redistribute it and/or modify
 * it under the terms of the GNU General Public License as published by
 * the Free Software Foundation; either version 2 of the License, or
 * (at your option) any later version.
 * 
 * This program is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 * GNU General Public License for more details.
 * 
 * You should have received a copy of the GNU General Public License
 * along with this program; if not, write to the Free Software
 * Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA  02111-1307  USA
 */
//package com.java2s;

public class Main {
    public static void main(String[] argv) throws Exception {
        String pi_Filename = "java2s.com";
        System.out.println(StyleSheet(pi_Filename));
    }

    /**
     * Gets the XML line that declares the stylesheet.
     * 
     * @param pi_Filename   Location of the stylesheet
     * @return String
     */
    public static String StyleSheet(String pi_Filename) {
        return "<?xml-stylesheet type=\"text/xsl\" href=\"" + pi_Filename
                + "\"?>\n";
    }
}

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