get XML Node by name - Java XML

Java examples for XML:XML Node

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Description

get XML Node by name

Demo Code

/*//www .ja v  a2  s  . c  o m
 * JBoss, Home of Professional Open Source
 * Copyright 2006, Red Hat Middleware LLC, and individual contributors
 * as indicated by the @author tags. 
 * See the copyright.txt in the distribution for a full listing 
 * of individual contributors.
 * This copyrighted material is made available to anyone wishing to use,
 * modify, copy, or redistribute it subject to the terms and conditions
 * of the GNU Lesser General Public License, v. 2.1.
 * This program is distributed in the hope that it will be useful, but WITHOUT A
 * WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A
 * PARTICULAR PURPOSE.  See the GNU Lesser General Public License for more details.
 * You should have received a copy of the GNU Lesser General Public License,
 * v.2.1 along with this distribution; if not, write to the Free Software
 * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
 * MA  02110-1301, USA.
 * 
 * (C) 2005-2006,
 * @author JBoss Inc.
 */
//package com.java2s;

public class Main {
    public static final org.w3c.dom.Node getNode(org.w3c.dom.Node element,
            String name) {
        org.w3c.dom.Node child = null;

        if (element != null) {
            org.w3c.dom.NodeList children = element.getChildNodes();

            for (int i = 0; i < children.getLength(); i++) {
                org.w3c.dom.Node item = children.item(i);

                if (item.getNodeName().equals(name)) {
                    child = item;

                    break;
                } else {
                    if (item.hasChildNodes()) {
                        child = getNode(item, name);

                        if (child != null)
                            break;
                    }
                }
            }
        }

        return child;
    }
}

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