Shows one single user in twitter - Java Social Media

Java examples for Social Media:Twitter

Description

Shows one single user in twitter

Demo Code

/*/*from w w w .  j a va2  s  .c o  m*/
 * Copyright 2007 Yusuke Yamamoto
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

package twitter4j.examples.user;

import twitter4j.Twitter;
import twitter4j.TwitterException;
import twitter4j.TwitterFactory;
import twitter4j.User;

/**
 * Shows one single user.
 *
 * @author Yusuke Yamamoto - yusuke at mac.com
 */
public final class ShowUser {
    /**
     * Usage: java twitter4j.examples.user.ShowUser [screen name]
     *
     * @param args message
     */
    public static void main(String[] args) {
        if (args.length < 1) {
            System.out
                    .println("Usage: java twitter4j.examples.user.ShowUser [screen name]");
            System.exit(-1);
        }
        try {
            Twitter twitter = new TwitterFactory().getInstance();
            User user = twitter.showUser(args[0]);
            if (user.getStatus() != null) {
                System.out.println("@" + user.getScreenName() + " - "
                        + user.getStatus().getText());
            } else {
                // the user is protected
                System.out.println("@" + user.getScreenName());
            }
            System.exit(0);
        } catch (TwitterException te) {
            te.printStackTrace();
            System.out.println("Failed to delete status: "
                    + te.getMessage());
            System.exit(-1);
        }
    }
}

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