True if bit at index in bits is one. - Java Language Basics

Java examples for Language Basics:Bit

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Description

True if bit at index in bits is one.

Demo Code

/*******************************************************************************
 *   Copyright 2014 Analog Devices, Inc.
 *
 *   Licensed under the Apache License, Version 2.0 (the "License");
 *   you may not use this file except in compliance with the License.
 *   You may obtain a copy of the License at
 *
 *       http://www.apache.org/licenses/LICENSE-2.0
 *
 *   Unless required by applicable law or agreed to in writing, software
 *   distributed under the License is distributed on an "AS IS" BASIS,
 *   WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 *   See the License for the specific language governing permissions and
 *   limitations under the License.//ww  w . j a va 2s  . co  m
 ********************************************************************************/
//package com.java2s;

public class Main {
    public static void main(String[] argv) throws Exception {
        int bits = 2;
        int index = 2;
        System.out.println(isBitSet(bits, index));
    }

    /**
     * True if bit at {@code index} in {@code bits} is one.
     * 
     * @param bits
     * @param index must be in the range [0,31] identifies which bit to clear.
     */
    public static boolean isBitSet(int bits, int index) {
        return (bits & (1 << index)) != 0;
    }

    /**
     * True if bit at {@code index} in {@code bits} is one.
     * 
     * @param bits
     * @param index must be in the range [0,63] identifies which bit to clear.
     */
    public static boolean isBitSet(long bits, int index) {
        return (bits & (1L << index)) != 0;
    }
}

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